New York Times, 04/03/24
For this one, I used an “X” move, and then contradiction. At Branch Point One, I considered the two possible values for S(1,7), and showed that, in either case, S(1,2) = 4.
For this one, I used an “X” move, and then contradiction. At Branch Point One, I considered the two possible values for S(1,7), and showed that, in either case, S(1,2) = 4.